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x^2-12.69x+40.19=0
a = 1; b = -12.69; c = +40.19;
Δ = b2-4ac
Δ = -12.692-4·1·40.19
Δ = 0.2761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.69)-\sqrt{0.2761}}{2*1}=\frac{12.69-\sqrt{0.2761}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.69)+\sqrt{0.2761}}{2*1}=\frac{12.69+\sqrt{0.2761}}{2} $
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